Use the formula p=2l+2w to find the length l of a rectangular lot if the width w is 45 feet and the perimeter p is 240 feet

240=2l+2(45) solve for l 
240=2l+90   240-90=150/2=75

Order of Operations:
BODMAS
Brackets; Other; Division; Multiplication; Addition; Subtraction.

5 + 2² - 3(6) ÷ 3
= 5 + 2² - 18 ÷ 3 
= 5 + 4 - 18 ÷ 3
= 5 + 4 - 6
= 3

-(3² -12) + 4 ÷ 2
= -3² + 12 + 4 ÷ 2
= -9 + 12 + 4 ÷ 2
= -9 + 12 + 2
= 5

7 × 2² ÷ 4 + 12
= 7 × 4 ÷ 4 + 12
= 7 × 1 + 12
= 7 + 12
= 19

6² + 4 - 3
= 36 + 4 - 3
= 40 - 3
= 37