Use the given point on the terminal side of angle θ to find the value of the trigonometric
function indicated.
sin θ ; (− 19, −9)

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Ответ:

Jasten

02.06.2022

Mathematics

On a unit circle, the point that corresponds to an angle of $0^{\circ}$ is at position $(1, \, 0)$ .

The point that corresponds to an angle of $90^{\circ}$ is at position $(0, \, 1)$ .

Step-by-step explanation:

On a cartesian plane, a unit circle is

a circle of radius

,centered at the origin $(0, \, 0)$ .

The circle crosses the x- and y-axis at four points:

$(1, \, 0)$ , $(0, \, 1)$ , $(-1,\, 0)$ , and $(0,\, -1)$ .

Join a point on the circle with the origin using a segment. The "angle" here likely refers to the counter-clockwise angle between the positive x-axis and that segment.

When the angle is equal to $0^\circ$ , the segment overlaps with the positive x-axis. The point is on both the circle and the positive x-axis. Its coordinates would be $(1, \, 0)$ .

To locate the point with a $90^{\circ}$ angle, rotate the $0^\circ$ segment counter-clockwise by $90^{\circ}$ . The segment would land on the positive y-axis. In other words, the $90^{\circ}$ -point would be at the intersection of the positive y-axis and the circle. Its coordinates would be $(0, \, 1)$ .

Type the correct answer in the box. use a comma to separate the x- and y-coordinates of each point.

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Use the given point on the terminal side of angle θ to find the value of the trigonometric function indicated. sin θ ; (− 19, −9)