Use the grouping method to factor the polynomial below completely. M+212 + 4x+8
A. (x + 2)(x+4)
B. (R+ 4)(x+4)
C. (x + 2)(x+2)
D. (x2+4)(x+2)

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Ответ:

salmirakayy4579

13.04.2022

Mathematics

2 and 10 are solutions of given expression x^2+20=12x

Step-by-step explanation:

Given expression x^2+20=12x

We have to find the values that are solutions of given expression.

Since, the given expression is a quadratic equation , thus the roots are the solutions of given expression.

Consider the given expression , x^2+20=12x

It can be written as , x^2-12x+20=0

We can solve the given quadratic equation using middle term splitting method,

-12x can be written as -2x - 10x

$x^2-12x+20=0\\\\ x^2-2x-10x+20=0\\\\$

x^2-12x+20=0

taking x common from first two terms and -10 common from last two terms, we have,

x(x-2)-10(x-2)=0

$\Rightarrow (x-2)(x-10)=0$

using zero product property, we have, $ab=0 \Rightarrow a=0\ or\ b=0$

$\Rightarrow (x-2)=0$ or $\Rightarrow (x-10)=0$

$\Rightarrow x=2$ or $\Rightarrow x=10$

Thus, 2 and 10 are solutions of given expression x^2+20=12x

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Use the grouping method to factor the polynomial below completely. M+212 + 4x+8 A. (x + 2)(x+4) B. (R+ 4)(x+4) C. (x + 2)(x+2) D. (x2+4)(x+2)