Mathematics: Use the law of sines to solve the following non right angles. me with these 2

Use the law of sines to solve the following non right

leekkk

09.01.2022

1. The interior angles of any triangle add to 180 degrees in measure. So

$m\angle A=(180-85-47)^\circ=48^\circ$

Then by the law of sines,

$\dfrac{\sin48^\circ}{19}=\dfrac{\sin85^\circ}b=\dfrac{\sin47^\circ}c\implies b\approx25.5,c\approx18.7$

2. By the law of sines,

$\dfrac{\sin\angle A}a=\dfrac{\sin\angle B}{16}=\dfrac{\sin104^\circ}{25}$

so that

$\sin\angle B=\dfrac{16\sin104^\circ}{25}\implies m\angle B\approx38.4^\circ$

Then

$m\angle A\approx(180-104-38.4)^\circ=37.6^\circ$

so that

$\dfrac{\sin\angle A}a=\dfrac{\sin104^\circ}{25}\implies a=\dfrac{25\sin\angle A}{\sin104^\circ}\approx15.7$

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2965276513

18.11.2022

C) (-4,-5)

Step-by-step explanation:

correct on Edge

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