Using the diagram below l, if angle P is 78 degrees and arc CB is 46, find arc AC

arc AC = 202°

Step-by-step explanation:

Based on the tangent-angle secant rule, the angle formed outside a circle by a secant and a tangent is equal to one-half the difference between the far arc and the near arc.

Thus:

m<P = ½(arc AC - arc CB)

Substitute

78° = ½(arc AC - 46°)

Multiply both sides by 2

2*78 = arc AC - 46

156 = arc AC - 46

Add 46 to both sides

156 + 46 = arc AC

202° = arc AC

arc AC = 202°

It is C, (10.75) squared

Step-by-step explanation:

It is not A, I did the test. so not (2)(10.75). So the only option is C