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ashleyann3052
29.06.2019 •
Mathematics
Using the elimination method how do i do 5x + 6y = 50 -x + 6y =26
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Ответ:
y = 5 and x = 4
Step-by-step explanation:
You need to get the same number either in front of both x's or both y's.
As there is already a value the same for both y's, we can already subtract the two equations:
5x - -x = 6x
6y - 6y = 0
50 - 26 = 24
6x = 24
Divide both sides by 6 to find x:
6x ÷ 6 = x
24 ÷ 6 = 4
x = 4
Substitute this value into first equation:
5(4) + 6y = 50
20 + 6y = 50
Move the +20 over to the other side making it a -20:
6y = 50 - 20
6y = 30
Divide both sides by 6:
6y ÷ 6 = 7
30 ÷ 6 = 5
So y = 5
This means that y = 5 and x = 4
Hope this helps!
Ответ:
Cosy° =![\frac{r}{q}](/tpl/images/0730/5863/fb69b.png)
Step-by-step explanation:
From the picture attached,
By applying all trigonometric ratios in the given right triangle,
Siny° =
= ![\frac{\text{Opposite side}}{\text{Hypotenuse}}](/tpl/images/0730/5863/ef708.png)
tany° =
= ![\frac{\text{Opposite side}}{\text{Adjacent side}}](/tpl/images/0730/5863/10612.png)
Therefore, Cosy° =![\frac{\text{Adjacent side}}{\text{Hypotenuse}}](/tpl/images/0730/5863/28977.png)
Cosy° =![\frac{r}{q}](/tpl/images/0730/5863/fb69b.png)
Therefore, Cosy° =
will be the answer.