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gissellebramwell
28.03.2021 •
Mathematics
Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 42m-by-42m square. Val says the area is 1005.48 m^2. Find the area enclosed by the figure. Use 3.14 for pi. What error might Val have made?
Thanks in advance!
I don't have anymore points so please make a good and accurate answer.
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Ответ:
Area of the enclosed figure = 3148.74![m^{2}](/tpl/images/1226/1907/ea326.png)
Step-by-step explanation:
Area enclosed by the figure = 2 x area of the semicircle + area of the square
For the semicircle,
radius =![\frac{diameter}{2}](/tpl/images/1226/1907/94176.png)
=![\frac{42}{2}](/tpl/images/1226/1907/d6814.png)
= 21 m
area of a semicircle =
x ![\pi r^{2}](/tpl/images/1226/1907/33306.png)
=
x 3.14 x ![(21)^{2}](/tpl/images/1226/1907/49470.png)
= 692.37![m^{2}](/tpl/images/1226/1907/ea326.png)
area of a square = length x length
= 42 x 42
= 1764![m^{2}](/tpl/images/1226/1907/ea326.png)
Thus,
area enclosed by the figure = 2 x 692.37 + 1764
= 3148.74![m^{2}](/tpl/images/1226/1907/ea326.png)
The total area enclosed bu the figure is 3148.74![m^{2}](/tpl/images/1226/1907/ea326.png)
Ответ:
Vertex: 5/2, -49/4
X intercept: (6,0), (-1,0)
Y intercept: (0.-6)
Step-by-step explanation:
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