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quan91
20.02.2020 •
Mathematics
We choose 500 numbers uniformly at random from the interval[1.5,4.8].(a) Approximate the probability of the event that less than 65 of the numbers startwith the digit one.(b) Approximate the probability of the event that more than 160 of the numbersstart with the digit 3.
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Ответ:
a = 0.0801
b = 0.1910
Step-by-step explanation:
a) probability of the event that numbers start with the digit 1 =P (1.5 < X <2)
=(2 - 1.5) / (4.8 - 1.5)=0.1515
mean =np
= 500 * 0.1515
= 75.76
std deviation =√(np (1 - p)) = 8.02)
probability of the event that less than 65 of the numbers start with the digit 1 = P(X < 65)
= P(Z < (64.5 - 75.76) / 8.02)
=P(Z < -1.4041)
= 0.0801
b) probability of the event of the numbers start with the digit 3 =P(3<X<4) =(4 - 3) / (4.8 - 1.5)
=0.3030
Here mean =np
= 500 * 0.3030
= 151.52
std deviation =√(np(1-p)) =10.28
probability of the event that more than 160 of the numbers start with the digit 3 = P(X > 160)
= 1 - P (Z < (160.5 - 151.52) / 10.28)
= 1 - P (Z < 0.8743)
= 1 - 0.8090
= 0.1910
Ответ: