Website a offers tickets to an event for $4.50 each plus a $12.25 handling fee, while website b offers the tickets for $6.00 plus a $1.75 handling fee. find how many tickets need to be purchased in order for the cost to be the same?

9.75 because when you add 4.50 and 12.50 you'll get 16.75. Then you add 6.00 and 1.75 and get 7.75. Then you take 16 and minus it by 7 and you'll get 9 and now you add
.75 to the 9 and you'll get 9.75

The cost through each website is a linear equation (y = mx+b).

Slope (m) is a rate and the fees are the y-intercept (b).

website A.
y = 4.5x + 12.25

website B.
y = 6x + 1.75

set the cost (y) equal and solve for the number of tickets (x).

6x + 1.75 = 4.5x + 12.25
6x - 4.5x = 12.25 - 1.75
1.5x = 10.5
x = 10.5/1.5
x = 7

The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.

Step-by-step explanation:

Assumptions:

1. The sampling from the different discussion sections was independent and random.

2. The populations are normal with means and constant variance

There's no variation among the discussion sections

There's variation among the discussion sections

                Df     Sum Sq       Mean sq    F value     Pr(>F)

Section     7       525.01         75             1.87            0.99986

Residuals  189    7584.11        40.13

Test Statistic =

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.