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yesimabadbih5147
20.10.2019 •
Mathematics
What are the coordinates of the vertex for f(x) = x2 + 6x + 13?
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Ответ:
y=ax²+bx+c or
f(x)=ax²+bx+c, then the x value of the vertex is -b/(2a)
so
given that the equation is
f(x)=1x²+6x+13
-b/2a=-6/(2*1)=-6/2=-3
the y value is found by subsituting -3 for x
f(-3)=(-3)²+6(-3)+13
f(-3)=9-18+13
f(-3)=4
the coordainates are (-3,4)
Ответ:
A
Step-by-step explanation:
The y-intercept is -2
The rate of change is 3
3x-2