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kristinaholahan
17.09.2020 •
Mathematics
What are the prime factors of 700
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Ответ:
Ответ:
(2^8 · 3^-5 ·6^0)^-2 · (3^-2/2^3)^4 · 2^28
First set of parenthesis:
2^8 = 256, 3^-5 = 0.00411522, 6^0 = 1
(256 * 0.00411522 * 1) = 1.05349794
1.05349794^-2 = 0.90101623
Second set of parenthesis:
3^-2 = 0.1111, 2^3 = 8
(0.111 / 8) = 0.0138
0.0138^4 = 0.00000003721088
Third set: 2^28 = 268435456
Final: 0.90101623 * 0.00000003721088 * 268435456 = 9
(2^8 · 3^-5 ·6^0)^-2 · (3^-2/2^3)^4 · 2^28 = 9