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cynayapartlow88
16.12.2020 •
Mathematics
What are the real and complex solutions to the following equation? -2x^4+2x^2+4=0
Show all steps.
u=±1i or u=±√2
u=±2i or u=±√2
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Ответ:
x = ± i, x = ±![\sqrt{2}](/tpl/images/0989/9963/7e821.png)
Step-by-step explanation:
Given
- 2
+ 2x² + 4 = 0 ( divide through by - 2 )
Use the substitution x² = u , then
u² - u - 2 = 0 ← in standard form
(u - 2)(u + 1) = 0 ← in factored form
Equate each factor to zero and solve for u
u - 2 = 0 ⇒ u = 2
u + 1 = 0 ⇒ u = - 1
Change back into terms of x, that is
x² = 2 ( take the square root of both sides )
x = ±![\sqrt{2}](/tpl/images/0989/9963/7e821.png)
x² = - 1 ( take the square root of both sides )
x = ±
= ± i
x = ±
← real solutions
x = ± i ← complex solutions
Ответ:
what are the chooses
EX: 5x+3=-8
Step-by-step explanation: