What are the solutions of the quadratic equation

Ответ:

barn01

10.03.2022

Mathematics

For this case we must find the solutions of the following quadratic equation:

2x ^ 2-2x-9 = 0

The roots will come from:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Where:

$a = 2\\b = -2\\c = -9$

Substituting:

$x = \frac {- (- 2) \pm \sqrt {(- 2) ^ 2-4 (2) (- 9)}} {2 (2)}\\x = \frac {2 \pm \sqrt {4 + 72}} {2 (2)}\\x = \frac {2 \pm \sqrt {76}} {4}\\x = \frac {2 \pm \sqrt {2 ^ 2 * 19}} {4}\\x = \frac {2 \pm2 \sqrt {19}} {4}$

The roots are:

$x_ {1} = \frac {2 + 2 \sqrt {19}} {4} = \frac {1+ \sqrt {19}} {2}\\x_ {2} = \frac {2-2 \sqrt {19}} {4} = \frac {1- \sqrt {19}} {2}$

Option C

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Ответ:

EmmaKozlewski2545

10.03.2022

Mathematics

Option C

The solutions of the quadratic equation are:

$x = \frac{1\±\sqrt{19}}{2}$

Step-by-step explanation:

Use the quadratic formula to solve this equation.

For a quadratic function of the form ax^2 +bx +c=0 the quadratic formula is:

$x = \frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case:

$a=2\\b=-2\\c=-9$

$x = \frac{-(-2)\±\sqrt{(-2)^2-4(2)(-9)}}{2(2)}$

$x = \frac{1\±\sqrt{19}}{2}$

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Ответ:

xoxonaynay

09.03.2021

Mathematics

They are designated by the principal energy level. (# of energy level = # of sublevels)
See attached pic.

How to find the number of sublevels in a principal energy level?

How to find the number of sublevels in a principal energy level?

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What are the solutions of the quadratic equation below? 2x2 - 2x - 9 = 0

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