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Carlosruelas5409
13.07.2020 •
Mathematics
What are the verter and x-intercepts of the graph of the function given below?
y=x2-2x-35
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Ответ:
For x intercepts, plug in 0 for y.
0 = (x^2) - 2x - 35
*factoring* = (x-7)(x+5)
x intercepts = 7,-5
As for the vertex, you can use the equation -b/2a for the x-coordinate of the vertex
so,
x = -b/2a = -(-2)/2 = 1
then just find the y value by plugging it back in to the equation.
y = ((1)^2) - 2(1) - 35
= -36
so, vertex is at (1,-36)
Ответ:
sorry
Step-by-step explanation: