dyllanmasters99
06.05.2020 •
Mathematics
What are the x-intercepts of the function f(x) = –2x2 – 3x + 20? (–4, 0) and five-halves five-halves and (4, 0) (–5, 0) and (2, 0) (–2, 0) and (5, 0)
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Ответ:
(-4, 0) and (5/2, 0)
Step-by-step explanation:
f(x) = –2x2 – 3x + 20
factor using the diamond method
-2*20 = -40
so -8 * 5 = -40 and -8 + 5 = -3 so...
f(x) = -2x^2 - 8x + 5x + 20
f(x) = -2x (x + 4) + 5 *(x + 4)
f(x) = (-2x + 5)*(x + 4)
x-intercepts are x = 5/2 and x =-4
(-4, 0) and (5/2, 0)
Ответ:
14 -w-
Step-by-step explanation: