What does d=1/2gt^2 solve? if g=gravity and t=halftime the distance from the ground to the peak, or the peak to the ground? (i am using this for my assignment as we are making rockets and we have to calculate the distance it travelled using the time.) we also have to list limitations of this formula so i was wondering whether the formula solves the distance of it going upwards or downwards, since the time of it going upwards and downwards are not always equal. if there are any limitations to list, let me know. you!

Physics is a bit difficult, I try to explain.

You know that the acceleration formula (to find the distance) is d=1/2at^2, when you have no initial distance and no initial speed.

d=1/2gt^2 is the formula for the Free Fall (the only acceleration that acts on the object is the Gravity Acceleration) and since we consider the y-axis positive when oriented up, it solves from ground to peak (object thrown upward).

The formula when the object goes downwards is d=v0t - 1/2gt^2

Hope it's clear, in case leave a comment.

Brenda weighs 17 pounds on Mars!

Step-by-step explanation:

If Andrew weighs 57 pounds on Mars then, 152-57= 95...

Alright so basically I mean just subtract 95 from 112 to get your answer

Hope that helped :)