What is 63 as the product of prime factors in ascending order?

When we arrange the numbers in such an order that it starts from the smallest number and goes towards the largest number, that order is called ascending order.
Prime factors of 63 are : 3, 3, 7
As 3 repeats and 3 is smaller than 7 so, when we write this in ascending order as the product of these, we write in such a way;
63 = 3 x 3 x 7 = 3² x 7
Now 3² = 9 and 9 is greater than 7,so,
63 = 7 x 9

The length of VZ is 10 units .

Step-by-step explanation:

As given

Z is the circumcenter of triangle TUV.

By using the properties of circumcentre .

The vertices of a triangle are equidistant from the circumcenter.

Thus

VZ = UZ = TZ

As given in the figure.

UZ = 3x + 4

TZ = 5x

As  UZ = TZ

3x + 4 = 5x

5x - 3x =4

2x = 4

x = 2

Put x = 2 in  UZ = 3x + 4 and TZ = 5x

UZ = 3 × 2+ 4

      = 6 + 4

      = 10 unit

TZ = 5 × 2

    = 10 unit

(As VZ = UZ = TZ )

Thus VZ = 10 units

Therefore the length of VZ is 10 units .