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s131845
24.02.2020 •
Mathematics
What is an equation of the line that s perpendicullar to y-3=-4(x+2) and passes through the point (-5,7)
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Ответ:
4y=x+33
y=x/4+33/4 (slope-intercept form)
Step-by-step explanation:
y-3 = -4(x+2)
y-3 -4x-8
y= -4x-8+3
y= -4x-5
m1 = -4
For perpendicularity
m2= -1/-4 = 1/4
The equation is
y-y1 = m2(x-x1)
y-7 = 1/4(x-(-5))
y-7 = x/4+5/4
Multiply through by 4
4y-28=x+5
4y=x+5+28
4y=x+33
Divide through by 4
y=x/4+33/4 (slope-intercept form)
Ответ:
15 feet of water spread
Step-by-step explanation:
Area of the circular pattern is 706.50 sq. feet
Area = A = π r^2 = (3.14)* r^2
706.50 = (3.14)* r^2
r^2 = 706.50 / 3.14
r^2 = 706.50 / 3.14
r = root (225)
r = 15 feet