What is an equation that models the date below
x 1,2,3,4,5
y 3,12,27,48,75

Ooh, a puzzle so we notice that the pairs are
(1,3)
(2,12)
(3,27)
(4,48)
(5,75)
we notice also that
1 times 3=3
2 times 6=12
3 times 9=27
4 times 12=48
5 times 15=75

the numbers go up by muliplues of 3
3,6,9,12,15
3=1 times 3
6=2 times 3
9=3 times 3
12=4 times 3
15=5 times 3
1st one is 1 times 1 times 3
2nd one is 2 times 2 times 3
3rd one is 3 times 3 times 3
4th one is 4 times 4 times 3
5th one is 5 times 5 times 3
so the equation by trial and error is
if the number is x then the equation is
x times (x times 3) or using associative propery which is a(bc)=(ab)c, the equaiton is

3x^2 which means 3 times (x^2)

so the equation is y=3x^2

XY = 2 units

Step-by-step explanation:

Given that :

ΔEFG ≅ ΔXYZ

Then, segments :

EF = XY, FG = YZ and EG = XZ

GIVEN THAT :

E (0, 0), F (0, 2), and G (3, 0)

We can find the distance between coordinates E (0, 0), F (0, 2) to get the measure of XY since they are both congruent.

EF = sqrt[(x2 - x1)^2 + (y2 - y1)^2]

x1 = 0, y1= 0, x2 = 0, y2 = 2

EF = sqrt[(0 - 0)^2 + (2 - 0)^2]

EF = sqrt[ 0 + 4]

EF = 2

SINCE EF = XY

XY = 2 units