kayciemarie9486
05.12.2021 •
Mathematics
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Ответ:
125 - 5x² = 0 when x = 5 sin θ
⇒ 125 - 5(5 sinθ)²
⇒ 125 - 5(25 sin²θ)
⇒ 125 - 125 sin²θ
⇒ 125(1 - sin²θ)
⇒ 125(1 - sinθ)(1 + sinθ) This is simplified
Solving for θ:
⇒ (1 - sinθ)(1 + sinθ) = 0
⇒ (1 - sinθ) = 0 (1 + sinθ) = 0
⇒ sinθ = 0 sinθ = -1
θ = 0° θ = 180°
Since neither value satisifies 0° < θ < 90° there is no solution