What is nearest ten to 399 and 402 and

141 and 582

Step-by-step explanation:

x,y,z are all single digit integers.

y = 4z - in order to be single digit, z must equal 0,1, or 2.

x = y-3 - since y is a single digit, the greatest x can be is 6 (when y is equal to 9). Assuming Y also has to be greater than three because x cannot be negative or equal to zero.

Based on this assumption, y cannot equal zero therefore z cannot equal zero.

If z=1, y=4, and x=1 making 141 a solution.

If z=2, y=8, and x=5 making 582 a solution.