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amunson40
26.10.2019 •
Mathematics
What is solution set for the quadratic equation ×^2 + 10×+25=0
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Ответ:
x=-5
Step-by-step explanation:
x squared+10x+25 factors into (x+5)(x+5). Set x equal to 0 and you get x=-5. To check, plug in negative 5 and you get 25+ -50 + 25=0 which is true.
Ответ:
Step-by-step explanation:
Let the number of 15 cent stamps be represented by X and
let the number of 25 cent stamps be represented by Y.
The equations would be as follows;
X+Y = 10
0.15X + 0.25Y = 1.70
To get X in terms of Y, use the first equation ; X = 10-Y
Next, replace X in the second equation by 10 -Y
0.15(10-Y) + 0.25Y = 1.70
1.5 -0.15Y +0.25Y = 1.70
Subtract 1.5 from both sides of the equation and sum up the Ys;
0.1Y = 1.70-1.5
0.1Y = 0.2
Divide both sides by 0.1;
Y = 0.2 / 0.1
Y = 2
Replace Y by 2 in any of the first to equations, I'll use X+Y=10;
X+2 =10
X= 8
Therefore, the 15 cents stamps are 8 and 0.25cents stamps are 2