What is the area, in square units, of the shaded region in the figure above?

Im pretty sure the Answer us B 34

w = x and ΔABC ~ ΔFED

Step-by-step explanation:

we know that

In a right triangle

If sin(A)=cos(B)

then

Angles A and B are complementary

so

A+B=90°

In this problem

If sin(y°) = cos(x°)

then

Angles y and x are complementary

so

x+y=90°

therefore

In the triangle FED

w+y=90° > by complementary angles

In the triangle ABC

z+x=90° > by complementary angles

so

w=x and z=y

Remember that

If two triangles are similar, then the corresponding angles are congruent

In this problem

The corresponding angles of triangles ABC and FED are congruent

therefore

ΔABC ~ ΔFED