Mathematics: What is the area of this figure?

What is the area of this figure?

u8p4

04.01.2022

Area of a square(A) is given by:

A = s^2 , where s is the side of the square.

Area of a triangle(A') is given by:

$A' = \frac{1}{2} \cdot b \cdot h$

From the given figure:

Labelled the diagram shown below.

In a triangle ABC:

BC = 5 cm and FA =4 cm

then;

$\text{A'} = \frac{1}{2} \cdot \text{BC} \cdot \text{FA}$

Substitute the given values we have;

$A' = \frac{1}{2} \cdot 5 \cdot 4 =5 \cdot 2= 10 cm^2$

Now, find the area of square BCDE:

Side of the square BCDE (s)= 5 cm

then;

A = (5)^2 = 25 cm^2

Then the area of the given composite figure :

A+A' = 25+10 = 35 cm^2

Therefore, the area of the given figure is, 35 cm^2

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makaylahollandmay21

19.04.2023

if my hipothosiss is corect is hall be 8x.

step by step:

you take the 8 and the x you multipliy them now thats 8 x's because 8 times x is 8x now we have 8x and that is the anser

Step-by-step explanation:

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