Mathematics: What is the area of this triangle? (image attached) enter your answer as a decimal in the box. round only your final answer to the nearest hundredth.

What is the area of this triangle? (image attached)

Ответ:

jeanbeansmith2p2ofty

17.01.2022

$\bf \textit{Law of Cosines}\\ \quad \\
c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies 
c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}\\\\
-----------------------------\\\\
\textit{so, let's find the missing side}
\\\\\\
c=\sqrt{2.7^2+3.4^2-2(2.7)(3.4)cos(40^o)}
\\\\\\
c=\sqrt{4.78542402433556327368}\implies c\approx 2.187561204706182220$

or we can round it, to say c = 2.19, so hmm that's the missing side
now, we use Heron's Formula, which uses all 3 sides only

$\bf \textit{Heron's Area Formula}\\\\
A=\sqrt{s(s-a)(s-b)(s-c)}\qquad 
\begin{cases}
a=2.7\\
b=3.4\\
c\approx 2.19\\\\
s=\cfrac{a+b+c}{2}
\end{cases}$

and that'd be the area of it

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Ответ:

hallkayleel0lozgxtq

01.11.2021

Mathematics

7) 2

8) 7/4

9) 4

10) 1/4

Step-by-step explanation:

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What is the area of this triangle? (image attached)

enter your answer as a decimal in the box. round only your final answer to the nearest hundredth.

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