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tannerlynn7227
07.01.2021 •
Mathematics
What is the area trapezoid ABCD A(-1,5) B(3,2) C(0,-2) D(-13,-11)
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Ответ:
62.5
Step-by-step explanation:
slope of AB = (5-2)/(-1 - 3) = -3/4
slope of BC = (2 - -2)/(3-0) = 4/3
AB ⊥ BC (slope -3/4 vs 4/3)
seg AB = √(-1 - 3)² + (5 - 2)² = √25 = 5
seg BC = √(3 - 0)² + (2 - -2)² = √25 = 5
seg AD = √(-1 - -13)² + (5 - -11)² = √400 = 20
Area (BC + AD) * AB / 2 = (5 + 20) * 5 / 2 = 62.5
Ответ:
1.
7x+11y-(5x+6y)
7x+11y-5x-6y
2x+5y
2.
13x+12y-(6x+2y)
13x+12y-6x-2y
7x+10y
3.
8x+8y-(4x-2y)
8x+8y-4x+8y
4x+16y
Let me know if this helps!