king514
06.10.2020 •
Mathematics
What is the center of a circle whose equation is x2 + y2 + 4x – 8y + 11 = 0?
(–2, 4)
(–4, 8)
(2, –4)
(4, –8)
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Ответ:
Step-by-step explanation:
eq. of circle is x²+y²+2gx+2fy+c=0
center=(-g,-k)
given eq. is x²+y²+4x-8y+11=0
comparing
2gx=4x
g=2
2fy=-8y
f=-4
center=(-2,4)
Ответ:
81/100
Step-by-step explanation:
Here's how to convert 0.81 to a fraction...
There is not much that can be done to figure out how to write 0.81 as a fraction, except to literally use what the decimal portion of your number, the .81, means.
Since there are 2 digits in 81, the very last digit is the "100th" decimal place.
So we can just say that .81 is the same as 81/100.
So your final answer is: 0.81 can be written as the fraction 81/100