What is the complement of the probability of landing on the number 4 when rolling a number cube?

answer: the possible set of three factors are {-11, -1, 1}, {-1,11} and {1,11}

explanation:

it is given that the product of three integer is 11.

we know that the number 11 is a prime number so the factors of 11 are 1 and 11.

since we have to multiply three factors so we will use negative integers also.

the four factors of 11 are -11, -1 ,1 and 11. we   have to find three unique integers whose product is 11.

so the possible set three unique integers is {-11, -1, 1}.

in this we have three factors -1, -1 and 11. since -1 is repeated and in a set repetition of elements are not allowed therefore the set is defined as {-1,11}.

in this we have three factors 1, 1 and 11. since 1 is repeated and in a set repetition of elements are not allowed therefore the set is defined as {1,11}.

for other arrangement of factors we get the a set from the above mentioned sets. therefore, all the possible set of three factors are {-11, -1, 1}, {-1,11} and {1,11}.