What is the correct answer for 8(12+15)+4?

220

Step-by-step explanation: Use distributive propetry and PEMDAS to solve.

Option C, would not be a fair game.

Step-by-step explanation:

You and a friend are playing a game using a spinner divided into 4 equal sections, numbered 1 to 4.

In the question there are 4 options given, we have to find out in which of the following would not be a fair game.

(A) You win if the pointer points at 1 or 2,

In this game, when pointer points 1 or 2, you win and when pointer points 3 or 4, your friend wins. So the probability that you win is  = 2/4 or 1/2.  So this would be a fair game.

(B) You win when the pointer points at an even number, otherwise your friend wins. There are 4 numbers on the spinner in which 2 numbers are even (2 and 4) and 2 numbers are odd (1 and 3). So the probability that you win is

2/4 or 1/2. So this would be a fair game.

(C) You win when the pointer points at any number except 3. In this case, when the pointer points at 1, 2 and 4 you win and when the pointer points on 3 your friend wins. So the probability that you win is 3/4 and the probability that your friend wins is 1/4. So this would not be a fair game.

Option C would not be a fair game.