coopera1744
17.07.2020 •
Mathematics
What is the equation of a circle with center (- 2, 3) and radius 4?
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Ответ:
(x+2)^2+(y-3)^2=16
Step-by-step explanation:
equation of a circle ( x - h )^2 + ( y - k )^2 = r^2
[x-(-2)]^2+(y-3)^2=4^2
(x+2)^2+(y-3)^2=16
Ответ:
x=0
y=-2
Step-by-step explanation:
x+4y=-8
x=-4y-8
4x+7y=-14
4(-4y-8)+7y=-14
-16y-32+7y=-14
-9y=-14+32
-9y=18
y=-2
x=-4*-2-8=8-8=0