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01.02.2020 •
Mathematics
What is the equation of a line that passes through -6, two and has a slope of -1/2
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Ответ:
slope (y2-y1)/(x2-x1)
m = (q--q)(p--p)
m = 2q/2p
m=q/p
point slope form
y-y1=m(x-x1)
y-q =q/p(x-p)
distribute
y-q=q/p *x -q
add q to each side
y = q/p *x
Step-by-step explanation:
Ответ: