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hernandezeileen20
25.07.2019 •
Mathematics
What is the equation of the axis of symmentry of the graph y + 3x -6 = -3(x-2)^2 + 4
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Ответ:
Then the equation of the axis of symmetry would be x = -b/(2a).
Can you finish this problem?
Hint: y + 3x -6 = -3(x-2)^2 + 4 becomes y + 3x - 6 = -3(x^2 - 4x + 4) + 4,
or y + 3x - 6 = -3x^2 - 12x + 12 + 4
Ответ: