What is the equation of the function that is graphed as line a? y4
15
b
XA
la
O y=2x-1
Oy=-x-1
Oy=-x
O y= 3x

What is the equation of the function that is graphed as line a?

y4
15
b
XA
la
O y=2x-1
Oy=-x-1
Oy

Solved

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Ответ:

hermesrobles

19.07.2020

Mathematics

Step-by-step explanation:

Obviously, we are letting u = x + 2. So what we have when we rewrite using this substitution is

u^2+12u-14=0 and we plug that into the quadratic formula with

a = 1, b = 12, c = -14:

$u=\frac{-12+-\sqrt{12^2-4(1)(-14)} }{2(1)}$ which can be simplified to

$u=\frac{-12+-\sqrt{144+56} }{2}$ and a bit more to

$u=\frac{-12+-\sqrt{200} }{2}$ and a tiny bit more to

$u=\frac{-12+-10\sqrt{2} }{2}$ and finally to

$u=-6+-5\sqrt{2}$ and plug back in for u:

x + 2 = -6 ± 5√2 and then subtract the 2 to get

x = -8 ± 5√2

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What is the equation of the function that is graphed as line a? y4 15 b XA la O y=2x-1 Oy=-x-1 Oy=-x O y= 3x