What is the equation of the line, in point-slope form, that goes through (-2,-1) and is perpendicular to y=5x+3? a. y-1=-1/5(x-2) b. y+1=-1/5(x+2) c. y+1=5(x+2) d. y-1=5(x-2)

The correct answer is B. y + 1 = -1/5 (x + 2)

I got B by putting the numbers in point-slope form which is y - y1 = m ( x - x1 ) so I got:     y + 1 = m ( x + 2 )

Then to find m(the slope) I knew if the slope was 5 it would be parallel to y=5x+3 so therefore -1/5 would be perpendicular to the line y=5x=3.

Hope that helps!!

2c^2

Step by step explanation: