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VoidedAngel
25.10.2019 •
Mathematics
What is the equation of the line in standard form?
a) 3x-y=-6
b) x-6y=-9
c) x+6y=9
d) 3x+y=6
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Ответ:
B
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 3, 1) and (x₂, y₂ ) = (3, 2)
m =
=
, thus
y =
x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (3, 2), then
2 =
+ c ⇒ c =
, thus
y =
x +
← in slope- intercept form
Multiply through by 6
6y = x + 9 ( subtract 6y from both sides )
0 = x - 6y + 9 ( subtract 9 from both sides )
- 9 = x - 6y, that is
x - 6y = - 9 ← in standard form → B
Ответ:
S/15
Step-by-step explanation: