What is the equation of the line that passes through the point (1, 3) and is perpendicular to the line 2x+3y=15?

y = 1.5x + 1.5

Step-by-step explanation:

First, plot 2x + 3y = 15 on a graph. Then plot (1,3) on a graph. After that, draw a line that passes through (1,3) and forms 90 degrees angles with 2x + 3y = 15. Then find the equation of that line by finding the y-intercept (0, 1.5). Then head up to the intersection point (1.6153846153846, 3.9230769230769). Subtract 1.5 from y. (2.4230769230769) Then divide by 1.5 (1.6153846153846). Reverse the operations you just did (in reverse order) to get the equation y = 1.5x + 1.5.

(I don't know how to explain this too well. Here's a graph to make more sense of it.)

BD does bisect the angle created by ABC, however it does not bisect segment AC. So it really depends on what you are determining the bisection to be.

Step-by-step explanation:

We can tell that it is bisecting the angle since it creates two congruent angles.

We can tell that it does not bisect the segment as AD and CD are not the same length.