applesass
22.09.2021 •
Mathematics
What is the equation of the line that passes through the point (1,7) and is perpendicular to the graph of Y=-14X+11
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Ответ:
Ответ:
its actually 10 points
x^4 + 9x^3 + 15x^2 + 9x + 14
Split 15x^2 into 14x^2 + x^2
x^4 + 9x^3 + 14x^2 + x^2 + 9x + 14 factor as
x^2 [x^2 + 9x + 14 ] + 1 [ x^2 + 9x + 14 ] take out GCF
[ x^2 + 1 ] [ x^2 + 9x + 14 ]
[ x^2 + 1 ] [ x + 7 ] [ x + 2 ]
mark brainliest