kevin2618
31.12.2019 •
Mathematics
What is the equation of the line that passes through the point (-6, -3) and is perpendicular to the line y = -0.4x
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Ответ:
y = 2.5 x + 12
Step-by-step explanation:
y = -0.4x
y = mx + b m = - 0.4 = - 4/10
slope (m') of line perpendicular to y=-0.4x m' = 10/4 = 2.5
y' = 2.5 x' + b' b' = (-3) - (2.5 x (-6)) = (-3) + 15 = 12
equation: y' = 2.5 x' + 12
Ответ:
55
Step-by-step explanation: