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danielahchf
13.10.2020 •
Mathematics
What is the equation of the line that passes through (6,4) and (4,1)
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Ответ:
y = 3/2*x - 5
Step-by-step explanation:
Lets say that P1=(6,4) and P2=(4,1) and that the form of the equation must be y=m*x+b where m is the slope and b the independent variable. Then having two given points we can use the slope formula to find the slope value as:
P1=(x1,y1) and P2=(x2,y2)
slope formula ---> m=(y2-y1)/(x2-x1)
Replacing the given points ---> m=(1-4)/(4-6) = 3/2
then replacing the slope value obtained:
y = 3/2*x + b
Now lets find the value of b. For this we have to replace in the equation a point it can be P1 or P2, i will replace P2:
1 = 3/2*4 + b
1 = 6 + b
1 - 6 = b
-5 = b
therefore the line equation is:
y = 3/2*x - 5
Ответ:
2+2=4
Hope this helps!