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girdwood797
29.06.2020 •
Mathematics
What is the equation of this circle in general form? x2+y2−6x−16=0 x2+y2+6x−16=0 x2+y2−6x+4=0 x² + y² + 6x + 4 = 0
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Ответ:
x² + y² - 6x - 16 = 0
Step-by-step explanation:
From the graph, the center point is (3, 0) and the radius is 5 so the standard equation is (x - 3)² + y² = 25. Let's turn this into general form now:
x² - 6x + 9 + y² = 25
x² + y² - 6x - 16 = 0
Ответ:
Step-by-step explanation:
Center = (a,b) = (3,0)
So, a = 3 and b = 0
Radius = 5
Now the equation of circle is given by:
=>![(x-a)^2+(y-a)^2 = r^2](/tpl/images/0696/9681/d2cc2.png)
Putting the values, we'll have
=>![(x-3)^2+(y-0)^2= 5^2](/tpl/images/0696/9681/bba90.png)
=>![(x-3)^2+y^2=25\\x^2-6x+9+y^2-25 = 0\\](/tpl/images/0696/9681/bc8ae.png)
=>![x^2+y^2-6x-16 = 0](/tpl/images/0696/9681/c9716.png)
So, This is the required generalized form
Ответ:
The answer is Circle .
Explanation:
Circle has an infinite sides .