What is the expanded form of -1\2(x-y)

D. On a coordinate plane, an exponential decay function decreases from quadrant 2 into quadrant 1 and approaches y = 0. It crosses the y-axis at (0, 3) and goes through (1, 2).

Step-by-step explanation:

All the option value differs only at the y-intercept and coordinate of the point where x=1 so we will focus on finding out those 2 coordinates. The function is

f(x)= 3* (2/3) ^x

f(x)= 3*

The y-intercept is the value of y when x=0. The calculation will be:

f(x)= 3*

f(0)= 3*

f(0)= 3*1

f(0)= 3

The coordinate will be (0, 3)

The value of y when x=1 will be:

f(x)= 3*

f(1)= 3*

f(1)=3*

f(1)= 2

The coordinate will be (1,2)

Then the answer will be D