What is the focal length of the parabola whose graph is shown? focus: (-3, 2.6) and directrix: (-0.6)

P=focal legnth is the distance from the focus to the vertex, which also is the disance from the directix to the vertex

therefor
distance from directix to focus=2 times focal legnth

find distance
horizontal distance
from y=-0.6 to y=2.6, that is distance ot 3 units
3/2=1.5
focal distance=1.5

Less than 1

Step-by-step explanation:

As 0.644 and 0.25 are less than 1, then

where p and q are greater than 1

then

But p.q is greater than 1, so 1/(p.q) is smaller than 1