What is the length of the shortest side of a triangle that has vertices at (-2, 5), (-2, -7), and (-6, -4)? a.) square root of 7 b.) 9 c.) 5 d.) square root of 5 times 2

Ithink you’re answering is d

Ididn't really get what u meant but this is an


find the area of an acute triangle with a base of 15 inches and a height of 4 inches.
solution: a= 1/2.b.h
                            a= 1/2.()
                              a= 60 in squared
                              a=30 in squared