What is the perimeter of a triangle with points at (−3, 3) , (3, 4) , and (3,-3)?

Let A = point (-3,3), B = point (3,4) and C = point (3,-3)

Using the distance formula (google it):

AB^2 = (-3-3)^2 + (3-4)^2
          = 36 + 1
   AB  = square root of 37 units
BC^2 = (3-3)^2 + (4+3)^2
          = 144
    BC = 12 units
AC^2 = (-3-3)^2 + (3+3)^2
          = 36 + 81
    AC = square root of 117 units

Perimeter = AB + BC +AC
                 = root 37 + 12 + root 117
                 = root 37 + 12 + 3 root 13

The correct answer is 4