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cranfordjacori
22.08.2019 •
Mathematics
What is the product of (2p + 7)(3p2 + 4p – 3)?
a=6p3 + 29p2 – 34p + 21
b=6p3 + 29p2 – 22p + 21
c=6p3 + 29p2 + 22p – 21
d=6p3 + 29p2 + 34p – 21
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Ответ:
To calculate the product, we need to multiply each member of each multiplier:
(2p + 7)(3p2 + 4p – 3) = 2p · 3p² + 2p · 4p + 2p · -3 + 7 ·3p² + 7 · 4p + 7 · -3
= 6p³ + 8p² - 6p + 21p² + 28p - 21
= 6p³ + 8p² + 21p² + 28p - 6p -21
= 6p³ + 29p² + 22p - 21
Therefore, the product of (2p + 7)(3p2 + 4p – 3) is 6p³ + 29p² + 22p -21
Ответ:
m∠3=180°. If she can get m∠2 and m∠3 to both equal the same expression, she can use the transitive property of equality to set them equal to each other.
How can Lily get m∠2 and m∠3 to both equal the same expression?
options:
A. She can measure m∠2 and m∠3 with a protractor.
B. She can subtract 180° from both sides of m∠1+m∠2=180° and m∠1+m∠3=180°.
C. She can subtract m∠1 from both sides of m∠1+m∠2=180° and m∠1+m∠3=180°.
D. She can subtract m∠1 from both sides of m∠1+m∠2=180°, and subtract m∠3 from both sides of m∠1+m∠3=180°.