Mathematics: What is the product? startfraction 5 k over 6 endfraction times startfraction 3 over 2 k cubed endfraction startfraction 5 over 4 k squared endfraction startfraction 5 k squared over 4 endfraction startfraction 5 k superscript 4 baseline over 4 endfraction startfraction 5 over 4 k superscript 4 baseline endfraction

What is the product? startfraction 5 k over 6 endfraction

Ответ:

minionsomg1

14.01.2022

$\frac{5}{4k^{2}}$

Step-by-step explanation:

We have the following expression and we need to simplify it using the rules of multiplication of fractions and multiplication and division of exponents with the same base:

$(\frac{5k}{6})(\frac{3}{2k^{3}})=\frac{15 k}{12 k^{3}}$

Simplifying:

$\frac{5}{4k^{2}}$

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Ответ:

DaisyHargrove23

14.01.2022

Mathematics

StartFraction 5 Over 4 k squared EndFraction

Step-by-step explanation:

We are asked to find the next product:

$\frac{5 k}{6} \times \frac{3}{2 k^3}$

Dividing numerator and denominator by k:

$\frac{5 \frac{k}{k}}{6} \times \frac{3}{2 \frac{k^3}{k}}$

$\frac{5}{6} \times \frac{3}{2 k^2}$

Dividing numerator and denominator by 3:

$\frac{5}{\frac{6}{3}} \times \frac{\frac{3}{3}}{2 k^2}$

$\frac{5}{2} \times \frac{1}{2 k^2} = \frac{5}{4 k^2}$

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Ответ:

Bescobar017

14.09.2020

Mathematics

The distance is 8.06.

You can solve this by using the distance formula.

d=√(x₂-x₁)²+(y₂-y₁)²
d=√(-2--9)²+(-2--6)²
d=√(7)²+(4)²
d=√49+16
d=√65
d=8.06

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