What is the quadratic portion in this quadratic equation 7x2-12x+16=0

x = 6/7 + (2 i sqrt(19))/7 or x = 6/7 - (2 i sqrt(19))/7

Step-by-step explanation:

Solve for x:

7 x^2 - 12 x + 16 = 0

Hint: | Write the quadratic equation in standard form.

Divide both sides by 7:

x^2 - (12 x)/7 + 16/7 = 0

Hint: | Solve the quadratic equation by completing the square.

Subtract 16/7 from both sides:

x^2 - (12 x)/7 = -16/7

Hint: | Take one half of the coefficient of x and square it, then add it to both sides.

Add 36/49 to both sides:

x^2 - (12 x)/7 + 36/49 = -76/49

Hint: | Factor the left hand side.

Write the left hand side as a square:

(x - 6/7)^2 = -76/49

Hint: | Eliminate the exponent on the left hand side.

Take the square root of both sides:

x - 6/7 = (2 i sqrt(19))/7 or x - 6/7 = -(2 i sqrt(19))/7

Hint: | Look at the first equation: Solve for x.

Add 6/7 to both sides:

x = 6/7 + (2 i sqrt(19))/7 or x - 6/7 = -(2 i sqrt(19))/7

Hint: | Look at the second equation: Solve for x.

Add 6/7 to both sides:

 x = 6/7 + (2 i sqrt(19))/7 or x = 6/7 - (2 i sqrt(19))/7

Question:

Which is the value of the expression

A. 1

B. 2

C. 8

D. 10

B. 2

Step-by-step explanation:

Given

Required

Evaluate

Split Fraction

From Laws of Indices

Applying this law to the above expression, we have

Also, from Laws of Indices

Applying this law to the above expression, we have

Multiply 10 by 1

Hence,