erinxmeow8
04.02.2020 •
Mathematics
What is the radius of the circle given by the equation below?
x2 - 4x + y2 - 4y - 73 = 0
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Ответ:
(x² - 4x )+( y² - 4y) - 73 = 0
(x² - 4x+4-4 )+( y² - 4y+4-4) - 73 = 0
(x² - 4x+4)-4 +( y² - 4y+4)-4 - 73 = 0
(x-2)² +(y-2)² = 9²
the radius is : 9
Ответ: