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26.05.2020 •
Mathematics
What is the range of the function y= ^3 sqaure root x+8?
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Ответ:
-∞≤y≤∞
Step-by-step explanation:
The given function is
y=(x+8)^{\frac{1}{3}}
Taking cube on both sides
y^3=x+8x=y^3-8
Hope this helps.
Ответ: