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Tnguyen8160
30.08.2019 •
Mathematics
What is the range of the function y=square x+5
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Ответ:
Option B is correct.
The range of the function is![y\geq 0](/tpl/images/0211/0575/d945b.png)
Explanation:
The function y=f(x) =![\sqrt{x+5}](/tpl/images/0211/0575/bb083.png)
The range of a function y=f(x) is the set of values y takes for all values of x within the domain of y=f(x).
The domain of given function f(x) is the set of all values of x in the interval![[-5, \infty)](/tpl/images/0211/0575/9017d.png)
As x takes values from -5 to
,
then,
takes values from
=0 to ![\sqrt{+\infty}](/tpl/images/0211/0575/b6696.png)
Therefore, the range of the y=
is given by:
or we can also write it as ![y\geq 0](/tpl/images/0211/0575/d945b.png)
Ответ:
You should know for y = sqrt(x) function, it's range is y >=0
Here it's the same thing.
Ответ:
a) $1.6225
b) 93.333...